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1104024411131 is a prime number
BaseRepresentation
bin10000000100001100111…
…110111001101111111011
310220112200100201000221212
4100010030332321233323
5121042020222124011
62203103134353335
7142522516441415
oct20041476715773
93815610630855
101104024411131
11396239aa8704
12159b7365b84b
1380155795b35
143b613b739b5
151dab8e4908b
hex1010cfb9bfb

1104024411131 has 2 divisors, whose sum is σ = 1104024411132. Its totient is φ = 1104024411130.

The previous prime is 1104024411121. The next prime is 1104024411137. The reversal of 1104024411131 is 1311144204011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1104024411131 - 226 = 1103957302267 is a prime.

It is a super-2 number, since 2×11040244111312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1104024411097 and 1104024411106.

It is not a weakly prime, because it can be changed into another prime (1104024411137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552012205565 + 552012205566.

It is an arithmetic number, because the mean of its divisors is an integer number (552012205566).

Almost surely, 21104024411131 is an apocalyptic number.

1104024411131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1104024411131 is an equidigital number, since it uses as much as digits as its factorization.

1104024411131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 1104024411131 its reverse (1311144204011), we get a palindrome (2415168615142).

The spelling of 1104024411131 in words is "one trillion, one hundred four billion, twenty-four million, four hundred eleven thousand, one hundred thirty-one".