Base | Representation |
---|---|
bin | 10000000100001101010… |
… | …100101111000001000111 |
3 | 10220112200202110210201200 |
4 | 100010031110233001013 |
5 | 121042023203244333 |
6 | 2203103501153543 |
7 | 142522616206233 |
oct | 20041524570107 |
9 | 3815622423650 |
10 | 1104030134343 |
11 | 396242257634 |
12 | 159b7555b8b3 |
13 | 80156a1ab56 |
14 | 3b6148235c3 |
15 | 1dab96c9c13 |
hex | 1010d52f047 |
1104030134343 has 24 divisors (see below), whose sum is σ = 1700664310800. Its totient is φ = 687741145344.
The previous prime is 1104030134341. The next prime is 1104030134351. The reversal of 1104030134343 is 3434310304011.
1104030134343 is a `hidden beast` number, since 1 + 10 + 4 + 0 + 301 + 3 + 4 + 343 = 666.
It is not a de Polignac number, because 1104030134343 - 21 = 1104030134341 is a prime.
It is a super-3 number, since 3×11040301343433 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1104030134341) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 25935148 + ... + 25977681.
It is an arithmetic number, because the mean of its divisors is an integer number (70861012950).
Almost surely, 21104030134343 is an apocalyptic number.
1104030134343 is a deficient number, since it is larger than the sum of its proper divisors (596634176457).
1104030134343 is a wasteful number, since it uses less digits than its factorization.
1104030134343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51912991 (or 51912988 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 27.
Adding to 1104030134343 its reverse (3434310304011), we get a palindrome (4538340438354).
The spelling of 1104030134343 in words is "one trillion, one hundred four billion, thirty million, one hundred thirty-four thousand, three hundred forty-three".
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