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BaseRepresentation
bin101010010101…
…111111010001
3202212221111022
4222111333101
510320200423
61033525225
7163230563
oct52257721
922787438
1011100113
1162a1752
123873815
1323b851b
14168d333
15e93dc8
hexa95fd1

11100113 has 2 divisors, whose sum is σ = 11100114. Its totient is φ = 11100112.

The previous prime is 11100101. The next prime is 11100119. The reversal of 11100113 is 31100111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6723649 + 4376464 = 2593^2 + 2092^2 .

It is a cyclic number.

It is not a de Polignac number, because 11100113 - 24 = 11100097 is a prime.

It is a super-2 number, since 2×111001132 = 246425017225538, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11100113.

It is not a weakly prime, because it can be changed into another prime (11100119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550056 + 5550057.

It is an arithmetic number, because the mean of its divisors is an integer number (5550057).

Almost surely, 211100113 is an apocalyptic number.

It is an amenable number.

11100113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11100113 is an equidigital number, since it uses as much as digits as its factorization.

11100113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 8.

The square root of 11100113 is about 3331.6832082297. The cubic root of 11100113 is about 223.0706674090.

Adding to 11100113 its reverse (31100111), we get a palindrome (42200224).

The spelling of 11100113 in words is "eleven million, one hundred thousand, one hundred thirteen".