1110313242133 has 4 divisors (see below), whose sum is σ = 1110366380448. Its totient is φ = 1110260103820.

The previous prime is 1110313242029. The next prime is 1110313242151. The reversal of 1110313242133 is 3312423130111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1110313242133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1110313242098 and 1110313242107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1110313242833) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26537803 + ... + 26579608.

It is an arithmetic number, because the mean of its divisors is an integer number (277591595112).

Almost surely, 2^{1110313242133} is an apocalyptic number.

It is an amenable number.

1110313242133 is a deficient number, since it is larger than the sum of its proper divisors (53138315).

1110313242133 is an equidigital number, since it uses as much as digits as its factorization.

1110313242133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 53138314.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1110313242133 its reverse (3312423130111), we get a palindrome (4422736372244).

The spelling of 1110313242133 in words is "one trillion, one hundred ten billion, three hundred thirteen million, two hundred forty-two thousand, one hundred thirty-three".