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11111009953 is a prime number
BaseRepresentation
bin10100101100100010…
…01000111010100001
31001200100022210021011
422112101020322201
5140223404304303
65034311300521
7542225012011
oct122621107241
931610283234
1011111009953
11479196a25a
1221a107a741
131080c24604
14775929c41
154506bb16d
hex296448ea1

11111009953 has 2 divisors, whose sum is σ = 11111009954. Its totient is φ = 11111009952.

The previous prime is 11111009933. The next prime is 11111009969. The reversal of 11111009953 is 35990011111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8253359104 + 2857650849 = 90848^2 + 53457^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11111009953 is a prime.

It is not a weakly prime, because it can be changed into another prime (11111009933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555504976 + 5555504977.

It is an arithmetic number, because the mean of its divisors is an integer number (5555504977).

Almost surely, 211111009953 is an apocalyptic number.

It is an amenable number.

11111009953 is a deficient number, since it is larger than the sum of its proper divisors (1).

11111009953 is an equidigital number, since it uses as much as digits as its factorization.

11111009953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1215, while the sum is 31.

The spelling of 11111009953 in words is "eleven billion, one hundred eleven million, nine thousand, nine hundred fifty-three".