Base | Representation |
---|---|

bin | 10100101100100100… |

… | …00001100100011101 |

3 | 1001200100202120120222 |

4 | 22112102001210131 |

5 | 140223434221023 |

6 | 5034320251125 |

7 | 542226666404 |

oct | 122622014435 |

9 | 31610676528 |

10 | 11111242013 |

11 | 4792008643 |

12 | 21a1170aa5 |

13 | 1080ca6121 |

14 | 77598a63b |

15 | 450714cc8 |

hex | 29648191d |

11111242013 has 8 divisors (see below), whose sum is σ = 11170104000. Its totient is φ = 11052410688.

The previous prime is 11111242001. The next prime is 11111242031. The reversal of 11111242013 is 31024211111.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11111242013 - 2^{16} = 11111176477 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to *n*+sod(*n*) for *n* = 11111241982 and 11111242000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11111242073) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1265045 + ... + 1273797.

It is an arithmetic number, because the mean of its divisors is an integer number (1396263000).

Almost surely, 2^{11111242013} is an apocalyptic number.

It is an amenable number.

11111242013 is a deficient number, since it is larger than the sum of its proper divisors (58861987).

11111242013 is an equidigital number, since it uses as much as digits as its factorization.

11111242013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15331.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 11111242013 its reverse (31024211111), we get a palindrome (42135453124).

The spelling of 11111242013 in words is "eleven billion, one hundred eleven million, two hundred forty-two thousand, thirteen".

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