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11112401141 is a prime number
BaseRepresentation
bin10100101100101100…
…11100100011110101
31001200102221110121122
422112112130203311
5140224233314031
65034401153325
7542242564652
oct122626344365
931612843548
1011112401141
11479272a4a6
1221a162b845
1310812c08ba
14775bacc29
1545089347b
hex29659c8f5

11112401141 has 2 divisors, whose sum is σ = 11112401142. Its totient is φ = 11112401140.

The previous prime is 11112401137. The next prime is 11112401147. The reversal of 11112401141 is 14110421111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8524644241 + 2587756900 = 92329^2 + 50870^2 .

It is an emirp because it is prime and its reverse (14110421111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11112401141 - 22 = 11112401137 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11112401147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556200570 + 5556200571.

It is an arithmetic number, because the mean of its divisors is an integer number (5556200571).

Almost surely, 211112401141 is an apocalyptic number.

It is an amenable number.

11112401141 is a deficient number, since it is larger than the sum of its proper divisors (1).

11112401141 is an equidigital number, since it uses as much as digits as its factorization.

11112401141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32, while the sum is 17.

Adding to 11112401141 its reverse (14110421111), we get a palindrome (25222822252).

The spelling of 11112401141 in words is "eleven billion, one hundred twelve million, four hundred one thousand, one hundred forty-one".