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111201412213 is a prime number
BaseRepresentation
bin110011110010000011…
…1101110010001110101
3101122000211002001002201
41213210013232101311
53310220030142323
6123030224104501
711014450256653
oct1474407562165
9348024061081
10111201412213
1143184330971
1219675165131
13a6423970c8
14554c99ddd3
152d5c8118ad
hex19e41ee475

111201412213 has 2 divisors, whose sum is σ = 111201412214. Its totient is φ = 111201412212.

The previous prime is 111201412193. The next prime is 111201412237. The reversal of 111201412213 is 312214102111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 95164229169 + 16037183044 = 308487^2 + 126638^2 .

It is an emirp because it is prime and its reverse (312214102111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111201412213 - 213 = 111201404021 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111201412243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55600706106 + 55600706107.

It is an arithmetic number, because the mean of its divisors is an integer number (55600706107).

Almost surely, 2111201412213 is an apocalyptic number.

It is an amenable number.

111201412213 is a deficient number, since it is larger than the sum of its proper divisors (1).

111201412213 is an equidigital number, since it uses as much as digits as its factorization.

111201412213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 111201412213 its reverse (312214102111), we get a palindrome (423415514324).

The spelling of 111201412213 in words is "one hundred eleven billion, two hundred one million, four hundred twelve thousand, two hundred thirteen".