Base | Representation |
---|---|
bin | 101010011101… |
… | …110001100000 |
3 | 202221120020022 |
4 | 222131301200 |
5 | 10322211000 |
6 | 1034333012 |
7 | 163422545 |
oct | 52356140 |
9 | 22846208 |
10 | 11132000 |
11 | 6313700 |
12 | 388a168 |
13 | 23c9ba9 |
14 | 169abcc |
15 | e9d585 |
hex | a9dc60 |
11132000 has 144 divisors (see below), whose sum is σ = 31370976. Its totient is φ = 3872000.
The previous prime is 11131999. The next prime is 11132003. The reversal of 11132000 is 23111.
It is a Harshad number since it is a multiple of its sum of digits (8).
It is a plaindrome in base 14.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11132003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 483989 + ... + 484011.
It is an arithmetic number, because the mean of its divisors is an integer number (217854).
Almost surely, 211132000 is an apocalyptic number.
11132000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 11132000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15685488).
11132000 is an abundant number, since it is smaller than the sum of its proper divisors (20238976).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11132000 is a wasteful number, since it uses less digits than its factorization.
11132000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 70 (or 41 counting only the distinct ones).
The product of its (nonzero) digits is 6, while the sum is 8.
The square root of 11132000 is about 3336.4651953827. The cubic root of 11132000 is about 223.2840662593.
Adding to 11132000 its reverse (23111), we get a palindrome (11155111).
Subtracting from 11132000 its reverse (23111), we obtain a square (11108889 = 33332).
It can be divided in two parts, 1113 and 2000, that added together give a palindrome (3113).
The spelling of 11132000 in words is "eleven million, one hundred thirty-two thousand".
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