Base | Representation |
---|---|
bin | 10000001100110110101… |
… | …000000110100110100011 |
3 | 10221102122200211212010010 |
4 | 100030312220012212203 |
5 | 121220031112342011 |
6 | 2211240545340003 |
7 | 143301635314665 |
oct | 20146650064643 |
9 | 3842580755103 |
10 | 1113313012131 |
11 | 39a176198061 |
12 | 15b926337603 |
13 | 80ca5c82648 |
14 | 3bc55632535 |
15 | 1de5e6321a6 |
hex | 10336a069a3 |
1113313012131 has 8 divisors (see below), whose sum is σ = 1484422225920. Its totient is φ = 742206236552.
The previous prime is 1113313012111. The next prime is 1113313012151. The reversal of 1113313012131 is 1312103133111.
It is an interprime number because it is at equal distance from previous prime (1113313012111) and next prime (1113313012151).
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1113313012131 - 25 = 1113313012099 is a prime.
It is a super-2 number, since 2×11133130121312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1113313012098 and 1113313012107.
It is not an unprimeable number, because it can be changed into a prime (1113313012111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1449790 + ... + 2080508.
It is an arithmetic number, because the mean of its divisors is an integer number (185552778240).
Almost surely, 21113313012131 is an apocalyptic number.
1113313012131 is a deficient number, since it is larger than the sum of its proper divisors (371109213789).
1113313012131 is an equidigital number, since it uses as much as digits as its factorization.
1113313012131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1219105.
The product of its (nonzero) digits is 162, while the sum is 21.
Adding to 1113313012131 its reverse (1312103133111), we get a palindrome (2425416145242).
The spelling of 1113313012131 in words is "one trillion, one hundred thirteen billion, three hundred thirteen million, twelve thousand, one hundred thirty-one".
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