Base | Representation |
---|---|
bin | 1010001000100001000100… |
… | …0011101010111111011111 |
3 | 1110110002222111200012211002 |
4 | 2202020101003222333133 |
5 | 2430020122410403043 |
6 | 35410145232020515 |
7 | 2226641024560454 |
oct | 242102103527737 |
9 | 43402874605732 |
10 | 11141431341023 |
11 | 3606066598815 |
12 | 12bb34a99173b |
13 | 62a82b6b8ca9 |
14 | 2a7368d1382b |
15 | 144c32db1bb8 |
hex | a22110eafdf |
11141431341023 has 2 divisors, whose sum is σ = 11141431341024. Its totient is φ = 11141431341022.
The previous prime is 11141431340983. The next prime is 11141431341041. The reversal of 11141431341023 is 32014313414111.
11141431341023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11141431341023 - 222 = 11141427146719 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11143431341023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5570715670511 + 5570715670512.
It is an arithmetic number, because the mean of its divisors is an integer number (5570715670512).
Almost surely, 211141431341023 is an apocalyptic number.
11141431341023 is a deficient number, since it is larger than the sum of its proper divisors (1).
11141431341023 is an equidigital number, since it uses as much as digits as its factorization.
11141431341023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 29.
Adding to 11141431341023 its reverse (32014313414111), we get a palindrome (43155744755134).
The spelling of 11141431341023 in words is "eleven trillion, one hundred forty-one billion, four hundred thirty-one million, three hundred forty-one thousand, twenty-three".
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