Base | Representation |
---|---|
bin | 1010001000100001000100… |
… | …0011101011000100000111 |
3 | 1110110002222111200020020001 |
4 | 2202020101003223010013 |
5 | 2430020122410410234 |
6 | 35410145232022131 |
7 | 2226641024561356 |
oct | 242102103530407 |
9 | 43402874606201 |
10 | 11141431341319 |
11 | 3606066598a64 |
12 | 12bb34a991947 |
13 | 62a82b6b9176 |
14 | 2a7368d1399d |
15 | 144c32db1d14 |
hex | a22110eb107 |
11141431341319 has 2 divisors, whose sum is σ = 11141431341320. Its totient is φ = 11141431341318.
The previous prime is 11141431341163. The next prime is 11141431341437. The reversal of 11141431341319 is 91314313414111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11141431341319 - 211 = 11141431339271 is a prime.
It is a super-2 number, since 2×111414313413192 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11141431342319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5570715670659 + 5570715670660.
It is an arithmetic number, because the mean of its divisors is an integer number (5570715670660).
Almost surely, 211141431341319 is an apocalyptic number.
11141431341319 is a deficient number, since it is larger than the sum of its proper divisors (1).
11141431341319 is an equidigital number, since it uses as much as digits as its factorization.
11141431341319 is an evil number, because the sum of its binary digits is even.
The product of its digits is 15552, while the sum is 37.
The spelling of 11141431341319 in words is "eleven trillion, one hundred forty-one billion, four hundred thirty-one million, three hundred forty-one thousand, three hundred nineteen".
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