Base | Representation |
---|---|
bin | 10100110111001001… |
… | …00111000001101111 |
3 | 1001220112202221210221 |
4 | 22123210213001233 |
5 | 140414200000421 |
6 | 5051210512211 |
7 | 544355300356 |
oct | 123344470157 |
9 | 31815687727 |
10 | 11200000111 |
11 | 4828120943 |
12 | 2206a35667 |
13 | 10964b1a01 |
14 | 78369299d |
15 | 4583e8841 |
hex | 29b92706f |
11200000111 has 2 divisors, whose sum is σ = 11200000112. Its totient is φ = 11200000110.
The previous prime is 11200000109. The next prime is 11200000139. The reversal of 11200000111 is 11100000211.
It is a weak prime.
It is an emirp because it is prime and its reverse (11100000211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11200000111 - 21 = 11200000109 is a prime.
Together with 11200000109, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 11200000094 and 11200000103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11200000411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5600000055 + 5600000056.
It is an arithmetic number, because the mean of its divisors is an integer number (5600000056).
Almost surely, 211200000111 is an apocalyptic number.
11200000111 is a deficient number, since it is larger than the sum of its proper divisors (1).
11200000111 is an equidigital number, since it uses as much as digits as its factorization.
11200000111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2, while the sum is 7.
Adding to 11200000111 its reverse (11100000211), we get a palindrome (22300000322).
The spelling of 11200000111 in words is "eleven billion, two hundred million, one hundred eleven", and thus it is an aban number.
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