Base | Representation |
---|---|
bin | 11001011111011010101011… |
… | …010010000110110000100111 |
3 | 112200221121210022210201100202 |
4 | 121133122223102012300213 |
5 | 104143303001130313112 |
6 | 1034234401252301115 |
7 | 32420455015622255 |
oct | 3137325322066047 |
9 | 480847708721322 |
10 | 112110110010407 |
11 | 327a36a343a583 |
12 | 106a783501179b |
13 | 4a72c26a6c732 |
14 | 1d9823044d5d5 |
15 | ce63942b86c2 |
hex | 65f6ab486c27 |
112110110010407 has 2 divisors, whose sum is σ = 112110110010408. Its totient is φ = 112110110010406.
The previous prime is 112110110010397. The next prime is 112110110010421. The reversal of 112110110010407 is 704010011011211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112110110010407 - 24 = 112110110010391 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112110110010497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56055055005203 + 56055055005204.
It is an arithmetic number, because the mean of its divisors is an integer number (56055055005204).
Almost surely, 2112110110010407 is an apocalyptic number.
112110110010407 is a deficient number, since it is larger than the sum of its proper divisors (1).
112110110010407 is an equidigital number, since it uses as much as digits as its factorization.
112110110010407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56, while the sum is 20.
Adding to 112110110010407 its reverse (704010011011211), we get a palindrome (816120121021618).
The spelling of 112110110010407 in words is "one hundred twelve trillion, one hundred ten billion, one hundred ten million, ten thousand, four hundred seven".
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