Base | Representation |
---|---|
bin | 10100111000100101… |
… | …10001001000101111 |
3 | 1001221101112200221021 |
4 | 22130102301020233 |
5 | 140430244201033 |
6 | 5052322115011 |
7 | 544563164416 |
oct | 123422611057 |
9 | 31841480837 |
10 | 11212100143 |
11 | 4833a35872 |
12 | 220aaaba67 |
13 | 1098b5a3aa |
14 | 78512247d |
15 | 4594d8b2d |
hex | 29c4b122f |
11212100143 has 2 divisors, whose sum is σ = 11212100144. Its totient is φ = 11212100142.
The previous prime is 11212100101. The next prime is 11212100161. The reversal of 11212100143 is 34100121211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11212100143 - 29 = 11212099631 is a prime.
It is a super-2 number, since 2×112121001432 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11212107143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606050071 + 5606050072.
It is an arithmetic number, because the mean of its divisors is an integer number (5606050072).
Almost surely, 211212100143 is an apocalyptic number.
11212100143 is a deficient number, since it is larger than the sum of its proper divisors (1).
11212100143 is an equidigital number, since it uses as much as digits as its factorization.
11212100143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 11212100143 its reverse (34100121211), we get a palindrome (45312221354).
The spelling of 11212100143 in words is "eleven billion, two hundred twelve million, one hundred thousand, one hundred forty-three".
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