Base | Representation |
---|---|
bin | 11001100001011110111011… |
… | …100101001101100010010001 |
3 | 112201110012100001201021211012 |
4 | 121201132323211031202101 |
5 | 104203114314022000441 |
6 | 1034423524423100305 |
7 | 32433643053405653 |
oct | 3141367345154221 |
9 | 481405301637735 |
10 | 112252117375121 |
11 | 32848945940519 |
12 | 1070b266ba1695 |
13 | 4a83438486ca9 |
14 | 1da10624d26d3 |
15 | ce9e063549eb |
hex | 6617bb94d891 |
112252117375121 has 2 divisors, whose sum is σ = 112252117375122. Its totient is φ = 112252117375120.
The previous prime is 112252117375019. The next prime is 112252117375147. The reversal of 112252117375121 is 121573711252211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 94401821923600 + 17850295451521 = 9716060^2 + 4224961^2 .
It is a cyclic number.
It is not a de Polignac number, because 112252117375121 - 234 = 112234937505937 is a prime.
It is not a weakly prime, because it can be changed into another prime (112252117375171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56126058687560 + 56126058687561.
It is an arithmetic number, because the mean of its divisors is an integer number (56126058687561).
Almost surely, 2112252117375121 is an apocalyptic number.
It is an amenable number.
112252117375121 is a deficient number, since it is larger than the sum of its proper divisors (1).
112252117375121 is an equidigital number, since it uses as much as digits as its factorization.
112252117375121 is an evil number, because the sum of its binary digits is even.
The product of its digits is 58800, while the sum is 41.
The spelling of 112252117375121 in words is "one hundred twelve trillion, two hundred fifty-two billion, one hundred seventeen million, three hundred seventy-five thousand, one hundred twenty-one".
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