112341324300233 has 4 divisors (see below), whose sum is σ = 128390084914560. Its totient is φ = 96292563685908.

The previous prime is 112341324300229. The next prime is 112341324300319. The reversal of 112341324300233 is 332003423143211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 112341324300233 - 2² = 112341324300229 is a prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 112341324300233.

It is not an unprimeable number, because it can be changed into a prime (112341324000233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8024380307153 + ... + 8024380307166.

It is an arithmetic number, because the mean of its divisors is an integer number (32097521228640).

Almost surely, 2^{112341324300233} is an apocalyptic number.

It is an amenable number.

112341324300233 is a deficient number, since it is larger than the sum of its proper divisors (16048760614327).

112341324300233 is an equidigital number, since it uses as much as digits as its factorization.

112341324300233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16048760614326.

The product of its (nonzero) digits is 31104, while the sum is 32.

Adding to 112341324300233 its reverse (332003423143211), we get a palindrome (444344747443444).

The spelling of 112341324300233 in words is "one hundred twelve trillion, three hundred forty-one billion, three hundred twenty-four million, three hundred thousand, two hundred thirty-three".