Base | Representation |
---|---|
bin | 1010001110011000001010… |
… | …1100011110010010111111 |
3 | 1110210201212211010021011021 |
4 | 2203212002230132102333 |
5 | 2433142331230011033 |
6 | 35524320512405011 |
7 | 2240134160153221 |
oct | 243460254362277 |
9 | 43721784107137 |
10 | 11242122110143 |
11 | 3644836938991 |
12 | 131696bb46767 |
13 | 637187355352 |
14 | 2ac19b9c8411 |
15 | 147677a98b2d |
hex | a3982b1e4bf |
11242122110143 has 2 divisors, whose sum is σ = 11242122110144. Its totient is φ = 11242122110142.
The previous prime is 11242122110119. The next prime is 11242122110173. The reversal of 11242122110143 is 34101122124211.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11242122110143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11242122110173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5621061055071 + 5621061055072.
It is an arithmetic number, because the mean of its divisors is an integer number (5621061055072).
Almost surely, 211242122110143 is an apocalyptic number.
11242122110143 is a deficient number, since it is larger than the sum of its proper divisors (1).
11242122110143 is an equidigital number, since it uses as much as digits as its factorization.
11242122110143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 11242122110143 its reverse (34101122124211), we get a palindrome (45343244234354).
The spelling of 11242122110143 in words is "eleven trillion, two hundred forty-two billion, one hundred twenty-two million, one hundred ten thousand, one hundred forty-three".
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