Base | Representation |
---|---|
bin | 10101000011000100… |
… | …10010100000001011 |
3 | 1002011112001021101110 |
4 | 22201202102200023 |
5 | 141120303230201 |
6 | 5105143221403 |
7 | 550011611625 |
oct | 124142224013 |
9 | 32145037343 |
10 | 11300055051 |
11 | 487964a67a |
12 | 2234447863 |
13 | 10b114450c |
14 | 792a99c15 |
15 | 4620ae6d6 |
hex | 2a189280b |
11300055051 has 4 divisors (see below), whose sum is σ = 15066740072. Its totient is φ = 7533370032.
The previous prime is 11300055029. The next prime is 11300055073. The reversal of 11300055051 is 15055000311.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (11300055029) and next prime (11300055073).
It is not a de Polignac number, because 11300055051 - 219 = 11299530763 is a prime.
It is a super-2 number, since 2×113000550512 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11300055451) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1883342506 + ... + 1883342511.
It is an arithmetic number, because the mean of its divisors is an integer number (3766685018).
Almost surely, 211300055051 is an apocalyptic number.
11300055051 is a deficient number, since it is larger than the sum of its proper divisors (3766685021).
11300055051 is an equidigital number, since it uses as much as digits as its factorization.
11300055051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3766685020.
The product of its (nonzero) digits is 375, while the sum is 21.
Adding to 11300055051 its reverse (15055000311), we get a palindrome (26355055362).
The spelling of 11300055051 in words is "eleven billion, three hundred million, fifty-five thousand, fifty-one".
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