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1130313131131 = 4937228947363
BaseRepresentation
bin10000011100101011111…
…010011010010001111011
311000001112110120101021011
4100130223322122101323
5122004340130144011
62223131513054351
7144443133043102
oct20345372322173
94001473511234
101130313131131
113a63aa328088
1216308b6b73b7
1382784cb7c62
143c9c9343039
151e606d2e621
hex1072be9a47b

1130313131131 has 4 divisors (see below), whose sum is σ = 1130542083432. Its totient is φ = 1130084178832.

The previous prime is 1130313131111. The next prime is 1130313131267. The reversal of 1130313131131 is 1311313130311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1130313131131 - 25 = 1130313131099 is a prime.

It is a super-2 number, since 2×11303131311312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1130313131111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 114468745 + ... + 114478618.

It is an arithmetic number, because the mean of its divisors is an integer number (282635520858).

Almost surely, 21130313131131 is an apocalyptic number.

1130313131131 is a deficient number, since it is larger than the sum of its proper divisors (228952301).

1130313131131 is an equidigital number, since it uses as much as digits as its factorization.

1130313131131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 228952300.

The product of its (nonzero) digits is 243, while the sum is 22.

Adding to 1130313131131 its reverse (1311313130311), we get a palindrome (2441626261442).

The spelling of 1130313131131 in words is "one trillion, one hundred thirty billion, three hundred thirteen million, one hundred thirty-one thousand, one hundred thirty-one".

Divisors: 1 4937 228947363 1130313131131