Base | Representation |
---|---|
bin | 110100101000101011… |
… | …0111101111101001011 |
3 | 101210202112122111120221 |
4 | 1221101112331331023 |
5 | 3322443214001011 |
6 | 123532133330511 |
7 | 11111043132214 |
oct | 1512126757513 |
9 | 353675574527 |
10 | 113034125131 |
11 | 43a348a9244 |
12 | 19aa6a96a37 |
13 | a874c9bc15 |
14 | 568415040b |
15 | 2e1867c971 |
hex | 1a515bdf4b |
113034125131 has 4 divisors (see below), whose sum is σ = 116680387264. Its totient is φ = 109387863000.
The previous prime is 113034125093. The next prime is 113034125143. The reversal of 113034125131 is 131521430311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113034125131 is a prime.
It is a super-2 number, since 2×1130341251312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 113034125096 and 113034125105.
It is not an unprimeable number, because it can be changed into a prime (113034125161) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1823131020 + ... + 1823131081.
It is an arithmetic number, because the mean of its divisors is an integer number (29170096816).
Almost surely, 2113034125131 is an apocalyptic number.
113034125131 is a deficient number, since it is larger than the sum of its proper divisors (3646262133).
113034125131 is an equidigital number, since it uses as much as digits as its factorization.
113034125131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3646262132.
The product of its (nonzero) digits is 1080, while the sum is 25.
Adding to 113034125131 its reverse (131521430311), we get a palindrome (244555555442).
The spelling of 113034125131 in words is "one hundred thirteen billion, thirty-four million, one hundred twenty-five thousand, one hundred thirty-one".
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