11304114041131 has 4 divisors (see below), whose sum is σ = 11304928648512. Its totient is φ = 11303299433752.

The previous prime is 11304114041123. The next prime is 11304114041201. The reversal of 11304114041131 is 13114041140311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11304114041131 - 2³ = 11304114041123 is a prime.

It is a super-3 number, since 3×11304114041131³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11304114041096 and 11304114041105.

It is not an unprimeable number, because it can be changed into a prime (11304114047131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 407282875 + ... + 407310628.

It is an arithmetic number, because the mean of its divisors is an integer number (2826232162128).

Almost surely, 2^{11304114041131} is an apocalyptic number.

11304114041131 is a deficient number, since it is larger than the sum of its proper divisors (814607381).

11304114041131 is an equidigital number, since it uses as much as digits as its factorization.

11304114041131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 814607380.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 11304114041131 its reverse (13114041140311), we get a palindrome (24418155181442).

The spelling of 11304114041131 in words is "eleven trillion, three hundred four billion, one hundred fourteen million, forty-one thousand, one hundred thirty-one".