Base | Representation |
---|---|
bin | 10000011100110010100… |
… | …010111010101111010111 |
3 | 11000001211012222002111011 |
4 | 100130302202322233113 |
5 | 122010102122210033 |
6 | 2223150530153051 |
7 | 144445653654334 |
oct | 20346242725727 |
9 | 4001735862434 |
10 | 1130424413143 |
11 | 3a6457124993 |
12 | 163100a22787 |
13 | 827a207b9bc |
14 | 3c9da02d98b |
15 | 1e6119b1ccd |
hex | 107328babd7 |
1130424413143 has 4 divisors (see below), whose sum is σ = 1130445620920. Its totient is φ = 1130403205368.
The previous prime is 1130424413093. The next prime is 1130424413147. The reversal of 1130424413143 is 3413144240311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1130424413143 - 213 = 1130424404951 is a prime.
It is a super-3 number, since 3×11304244131433 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1130424413147) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10523733 + ... + 10630606.
It is an arithmetic number, because the mean of its divisors is an integer number (282611405230).
Almost surely, 21130424413143 is an apocalyptic number.
1130424413143 is a deficient number, since it is larger than the sum of its proper divisors (21207777).
1130424413143 is an equidigital number, since it uses as much as digits as its factorization.
1130424413143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21207776.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 1130424413143 its reverse (3413144240311), we get a palindrome (4543568653454).
The spelling of 1130424413143 in words is "one trillion, one hundred thirty billion, four hundred twenty-four million, four hundred thirteen thousand, one hundred forty-three".
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