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BaseRepresentation
bin10101000011100101…
…11010001110000001
31002011211020122001011
422201302322032001
5141122412141113
65105420440521
7550063626325
oct124162721601
932154218034
1011304412033
114881056092
1222359a9141
1310b200b705
147934b1985
1546267063d
hex2a1cba381

11304412033 has 2 divisors, whose sum is σ = 11304412034. Its totient is φ = 11304412032.

The previous prime is 11304412001. The next prime is 11304412039. The reversal of 11304412033 is 33021440311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9962435344 + 1341976689 = 99812^2 + 36633^2 .

It is a cyclic number.

It is not a de Polignac number, because 11304412033 - 25 = 11304412001 is a prime.

It is a super-3 number, since 3×113044120333 (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11304411995 and 11304412013.

It is not a weakly prime, because it can be changed into another prime (11304412039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5652206016 + 5652206017.

It is an arithmetic number, because the mean of its divisors is an integer number (5652206017).

Almost surely, 211304412033 is an apocalyptic number.

It is an amenable number.

11304412033 is a deficient number, since it is larger than the sum of its proper divisors (1).

11304412033 is an equidigital number, since it uses as much as digits as its factorization.

11304412033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 11304412033 its reverse (33021440311), we get a palindrome (44325852344).

The spelling of 11304412033 in words is "eleven billion, three hundred four million, four hundred twelve thousand, thirty-three".