Base | Representation |
---|---|
bin | 100001101101001… |
… | …1101110011101110 |
3 | 2220211012022211210 |
4 | 1003122131303232 |
5 | 4304014330220 |
6 | 304121255250 |
7 | 40012303032 |
oct | 10332356356 |
9 | 2824168753 |
10 | 1131011310 |
11 | 5304765a0 |
12 | 276934526 |
13 | 15041b080 |
14 | aa2d21c2 |
15 | 6945e6e0 |
hex | 4369dcee |
1131011310 has 128 divisors (see below), whose sum is σ = 3299304960. Its totient is φ = 244339200.
The previous prime is 1131011239. The next prime is 1131011311. The reversal of 1131011310 is 131101311.
It is a super-2 number, since 2×11310113102 = 2558373166695832200, which contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1131011311) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 119865 + ... + 128955.
It is an arithmetic number, because the mean of its divisors is an integer number (25775820).
Almost surely, 21131011310 is an apocalyptic number.
1131011310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 1131011310, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1649652480).
1131011310 is an abundant number, since it is smaller than the sum of its proper divisors (2168293650).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1131011310 is a wasteful number, since it uses less digits than its factorization.
1131011310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9154.
The product of its (nonzero) digits is 9, while the sum is 12.
The square root of 1131011310 is about 33630.5115928973. The cubic root of 1131011310 is about 1041.8910705302.
Adding to 1131011310 its reverse (131101311), we get a palindrome (1262112621).
Subtracting from 1131011310 its reverse (131101311), we obtain a palindrome (999909999).
It can be divided in two parts, 113101 and 1310, that added together give a palindrome (114411).
The spelling of 1131011310 in words is "one billion, one hundred thirty-one million, eleven thousand, three hundred ten".
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