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11312130001333 = 74613505463279
BaseRepresentation
bin1010010010011100111101…
…1111011000100110110101
31111001102120210022121201011
42210213033133120212311
52440314220240020313
640020415404432221
72245163061340240
oct244471737304665
944042523277634
1011312130001333
1136714a152a7a7
121328449548671
13640963303735
142b171d696257
151493c3c1793d
hexa49cf7d89b5

11312130001333 has 8 divisors (see below), whose sum is σ = 12956192282880. Its totient is φ = 9675078647280.

The previous prime is 11312130001223. The next prime is 11312130001343. The reversal of 11312130001333 is 33310003121311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11312130001333 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11312130001343) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1752728413 + ... + 1752734866.

It is an arithmetic number, because the mean of its divisors is an integer number (1619524035360).

Almost surely, 211312130001333 is an apocalyptic number.

It is an amenable number.

11312130001333 is a deficient number, since it is larger than the sum of its proper divisors (1644062281547).

11312130001333 is an equidigital number, since it uses as much as digits as its factorization.

11312130001333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3505463747.

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 11312130001333 its reverse (33310003121311), we get a palindrome (44622133122644).

The spelling of 11312130001333 in words is "eleven trillion, three hundred twelve billion, one hundred thirty million, one thousand, three hundred thirty-three".

Divisors: 1 7 461 3227 3505463279 24538242953 1616018571619 11312130001333