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113123142151 is a prime number
BaseRepresentation
bin110100101011010101…
…0100010101000000111
3101210222202011000222121
41221112222202220013
53323134011022101
6123545033310411
711113203562105
oct1512652425007
9353882130877
10113123142151
1143a80079028
1219b10865407
13a88a568606
145691cc2c75
152e213b30a1
hex1a56aa2a07

113123142151 has 2 divisors, whose sum is σ = 113123142152. Its totient is φ = 113123142150.

The previous prime is 113123142137. The next prime is 113123142161. The reversal of 113123142151 is 151241321311.

It is a strong prime.

It is an emirp because it is prime and its reverse (151241321311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113123142151 - 231 = 110975658503 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113123142101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56561571075 + 56561571076.

It is an arithmetic number, because the mean of its divisors is an integer number (56561571076).

Almost surely, 2113123142151 is an apocalyptic number.

113123142151 is a deficient number, since it is larger than the sum of its proper divisors (1).

113123142151 is an equidigital number, since it uses as much as digits as its factorization.

113123142151 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 720, while the sum is 25.

Adding to 113123142151 its reverse (151241321311), we get a palindrome (264364463462).

The spelling of 113123142151 in words is "one hundred thirteen billion, one hundred twenty-three million, one hundred forty-two thousand, one hundred fifty-one".