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BaseRepresentation
bin101011001010…
…001110111111
3210021211001011
4223022032333
510344022421
61042300051
7165111514
oct53121677
923254034
1011314111
116428506
123957627
132461a53
14170730b
15ed74e1
hexaca3bf

11314111 has 2 divisors, whose sum is σ = 11314112. Its totient is φ = 11314110.

The previous prime is 11314109. The next prime is 11314123. The reversal of 11314111 is 11141311.

It is a happy number.

It is a m-pointer prime, because the next prime (11314123) can be obtained adding 11314111 to its product of digits (12).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11314111 - 21 = 11314109 is a prime.

Together with 11314109, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 11314091 and 11314100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11312111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657055 + 5657056.

It is an arithmetic number, because the mean of its divisors is an integer number (5657056).

Almost surely, 211314111 is an apocalyptic number.

11314111 is a deficient number, since it is larger than the sum of its proper divisors (1).

11314111 is an equidigital number, since it uses as much as digits as its factorization.

11314111 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 12, while the sum is 13.

The square root of 11314111 is about 3363.6454926166. The cubic root of 11314111 is about 224.4950718409.

Adding to 11314111 its reverse (11141311), we get a palindrome (22455422).

The spelling of 11314111 in words is "eleven million, three hundred fourteen thousand, one hundred eleven".