113200211303 has 4 divisors (see below), whose sum is σ = 119859047280. Its totient is φ = 106541375328.

The previous prime is 113200211273. The next prime is 113200211363. The reversal of 113200211303 is 303112002311.

113200211303 = T₆₆₆₀₂ + T₆₆₆₀₃ + ... + T₆₆₆₅₂.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 303112002311 = 17 ⋅17830117783.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113200211303 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (17), and also a Moran number because the ratio is a prime number: 6658835959 = 113200211303 / (1 + 1 + 3 + 2 + 0 + 0 + 2 + 1 + 1 + 3 + 0 + 3).

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113200211363) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3329417963 + ... + 3329417996.

It is an arithmetic number, because the mean of its divisors is an integer number (29964761820).

Almost surely, 2^113200211303 is an apocalyptic number.

113200211303 is a deficient number, since it is larger than the sum of its proper divisors (6658835977).

113200211303 is an equidigital number, since it uses as much as digits as its factorization.

113200211303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6658835976.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 113200211303 its reverse (303112002311), we get a palindrome (416312213614).

The spelling of 113200211303 in words is "one hundred thirteen billion, two hundred million, two hundred eleven thousand, three hundred three".