113301300113 has 6 divisors (see below), whose sum is σ = 114122300994. Its totient is φ = 112486163664.

The previous prime is 113301300041. The next prime is 113301300191. The reversal of 113301300113 is 311003103311.

It can be written as a sum of positive squares in only one way, i.e., 102920339344 + 10380960769 = 320812^2 + 101887^2 .

It is not a de Polignac number, because 113301300113 - 2¹⁴ = 113301283729 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113301300091 and 113301300100.

It is not an unprimeable number, because it can be changed into a prime (113301300713) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 2912756 + ... + 2951397.

It is an arithmetic number, because the mean of its divisors is an integer number (19020383499).

Almost surely, 2^113301300113 is an apocalyptic number.

It is an amenable number.

113301300113 is a deficient number, since it is larger than the sum of its proper divisors (821000881).

113301300113 is an frugal number, since it uses more digits than its factorization.

113301300113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5864431 (or 5864292 counting only the distinct ones).

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 113301300113 its reverse (311003103311), we get a palindrome (424304403424).

The spelling of 113301300113 in words is "one hundred thirteen billion, three hundred one million, three hundred thousand, one hundred thirteen".