11331033210133 has 24 divisors (see below), whose sum is σ = 14232977110968. Its totient is φ = 8941177478016.

The previous prime is 11331033210131. The next prime is 11331033210173. The reversal of 11331033210133 is 33101233013311.

11331033210133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 4 ways, for example, as 3243482135089 + 8087551075044 = 1800967^2 + 2843862^2 .

It is not a de Polignac number, because 11331033210133 - 2¹ = 11331033210131 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11331033210098 and 11331033210107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11331033210131) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 23607066 + ... + 24082267.

It is an arithmetic number, because the mean of its divisors is an integer number (593040712957).

Almost surely, 2^{11331033210133} is an apocalyptic number.

11331033210133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11331033210133 is a deficient number, since it is larger than the sum of its proper divisors (2901943900835).

11331033210133 is a wasteful number, since it uses less digits than its factorization.

11331033210133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47689733 (or 47689726 counting only the distinct ones).

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 11331033210133 its reverse (33101233013311), we get a palindrome (44432266223444).

The spelling of 11331033210133 in words is "eleven trillion, three hundred thirty-one billion, thirty-three million, two hundred ten thousand, one hundred thirty-three".