Base | Representation |
---|---|
bin | 1010010011100011101111… |
… | …1110101101010101100111 |
3 | 1111010020121221012122010112 |
4 | 2210320323332231111213 |
5 | 2441122123241134343 |
6 | 40033241013043235 |
7 | 2246434652005235 |
oct | 244707376552547 |
9 | 44106557178115 |
10 | 11331130021223 |
11 | 3679561549981 |
12 | 133007062651b |
13 | 6426a077a25c |
14 | 2b2602c37955 |
15 | 149b36ca8218 |
hex | a4e3bfad567 |
11331130021223 has 2 divisors, whose sum is σ = 11331130021224. Its totient is φ = 11331130021222.
The previous prime is 11331130021219. The next prime is 11331130021229. The reversal of 11331130021223 is 32212003113311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11331130021223 - 22 = 11331130021219 is a prime.
It is a super-2 number, since 2×113311300212232 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11331130021229) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665565010611 + 5665565010612.
It is an arithmetic number, because the mean of its divisors is an integer number (5665565010612).
Almost surely, 211331130021223 is an apocalyptic number.
11331130021223 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331130021223 is an equidigital number, since it uses as much as digits as its factorization.
11331130021223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 11331130021223 its reverse (32212003113311), we get a palindrome (43543133134534).
The spelling of 11331130021223 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty million, twenty-one thousand, two hundred twenty-three".
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