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11331131333113 = 15492773138519
BaseRepresentation
bin1010010011100011110000…
…0011101101100111111001
31111010020122000200021201001
42210320330003231213321
52441122124110124423
640033241101125001
72246434666111054
oct244707403554771
944106560607631
1011331131333113
113679562265589
121330070b59761
136426a0b19417
142b2603099a9b
hexa4e3c0ed9f9

11331131333113 has 4 divisors (see below), whose sum is σ = 11331204626560. Its totient is φ = 11331058039668.

The previous prime is 11331131333069. The next prime is 11331131333129. The reversal of 11331131333113 is 31133313113311.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11331131333113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11331131333153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36414333 + ... + 36724186.

It is an arithmetic number, because the mean of its divisors is an integer number (2832801156640).

Almost surely, 211331131333113 is an apocalyptic number.

It is an amenable number.

11331131333113 is a deficient number, since it is larger than the sum of its proper divisors (73293447).

11331131333113 is an equidigital number, since it uses as much as digits as its factorization.

11331131333113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 73293446.

The product of its digits is 2187, while the sum is 28.

Adding to 11331131333113 its reverse (31133313113311), we get a palindrome (42464444446424).

The spelling of 11331131333113 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, three hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 154927 73138519 11331131333113