11343203525433 has 32 divisors (see below), whose sum is σ = 16824395169792. Its totient is φ = 6750713736000.

The previous prime is 11343203525393. The next prime is 11343203525447. The reversal of 11343203525433 is 33452530234311.

11343203525433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 11343203525433 - 2⁶ = 11343203525369 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (39).

It is a junction number, because it is equal to n+sod(n) for n = 11343203525391 and 11343203525400.

It is not an unprimeable number, because it can be changed into a prime (11343203525453) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1356993 + ... + 4952558.

It is an arithmetic number, because the mean of its divisors is an integer number (525762349056).

Almost surely, 2^{11343203525433} is an apocalyptic number.

11343203525433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11343203525433 is a deficient number, since it is larger than the sum of its proper divisors (5481191644359).

11343203525433 is a wasteful number, since it uses less digits than its factorization.

11343203525433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6311085.

The product of its (nonzero) digits is 388800, while the sum is 39.

Adding to 11343203525433 its reverse (33452530234311), we get a palindrome (44795733759744).

The spelling of 11343203525433 in words is "eleven trillion, three hundred forty-three billion, two hundred three million, five hundred twenty-five thousand, four hundred thirty-three".