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11343341 = 22350867
BaseRepresentation
bin101011010001…
…010111101101
3210100022010202
4223101113231
510400441331
61043043245
7165262652
oct53212755
923308122
1011343341
116448469
123970525
132472149
141713c29
15ee0ecb
hexad15ed

11343341 has 4 divisors (see below), whose sum is σ = 11394432. Its totient is φ = 11292252.

The previous prime is 11343337. The next prime is 11343359. The reversal of 11343341 is 14334311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14334311 = 19772763.

It is a cyclic number.

It is not a de Polignac number, because 11343341 - 22 = 11343337 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11343331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25211 + ... + 25656.

It is an arithmetic number, because the mean of its divisors is an integer number (2848608).

Almost surely, 211343341 is an apocalyptic number.

It is an amenable number.

11343341 is a deficient number, since it is larger than the sum of its proper divisors (51091).

11343341 is an equidigital number, since it uses as much as digits as its factorization.

11343341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51090.

The product of its digits is 432, while the sum is 20.

The square root of 11343341 is about 3367.9876781247. The cubic root of 11343341 is about 224.6882332267.

Adding to 11343341 its reverse (14334311), we get a palindrome (25677652).

The spelling of 11343341 in words is "eleven million, three hundred forty-three thousand, three hundred forty-one".

Divisors: 1 223 50867 11343341