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113433554450 = 25218913119953
BaseRepresentation
bin110100110100100101…
…0101010111000010010
3101211210101020121121102
41221221022222320102
53324302442220300
6124035522424402
711123663206166
oct1515112527022
9354711217542
10113433554450
114411a314417
1219b98802102
13a909970828
1456c1206ca6
152e3d77c0d5
hex1a692aae12

113433554450 has 24 divisors (see below), whose sum is σ = 210999325908. Its totient is φ = 45370644480.

The previous prime is 113433554393. The next prime is 113433554467. The reversal of 113433554450 is 54455334311.

It can be written as a sum of positive squares in 6 ways, for example, as 98729809369 + 14703745081 = 314213^2 + 121259^2 .

It is a super-2 number, since 2×1134335544502 (a number of 23 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 885674 + ... + 1005626.

Almost surely, 2113433554450 is an apocalyptic number.

113433554450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

113433554450 is a deficient number, since it is larger than the sum of its proper divisors (97565771458).

113433554450 is a wasteful number, since it uses less digits than its factorization.

113433554450 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 138878 (or 138873 counting only the distinct ones).

The product of its (nonzero) digits is 216000, while the sum is 38.

Adding to 113433554450 its reverse (54455334311), we get a palindrome (167888888761).

The spelling of 113433554450 in words is "one hundred thirteen billion, four hundred thirty-three million, five hundred fifty-four thousand, four hundred fifty".

Divisors: 1 2 5 10 25 50 18913 37826 94565 119953 189130 239906 472825 599765 945650 1199530 2998825 5997650 2268671089 4537342178 11343355445 22686710890 56716777225 113433554450