Base | Representation |
---|---|
bin | 110100110100100101… |
… | …0101010111000010010 |
3 | 101211210101020121121102 |
4 | 1221221022222320102 |
5 | 3324302442220300 |
6 | 124035522424402 |
7 | 11123663206166 |
oct | 1515112527022 |
9 | 354711217542 |
10 | 113433554450 |
11 | 4411a314417 |
12 | 19b98802102 |
13 | a909970828 |
14 | 56c1206ca6 |
15 | 2e3d77c0d5 |
hex | 1a692aae12 |
113433554450 has 24 divisors (see below), whose sum is σ = 210999325908. Its totient is φ = 45370644480.
The previous prime is 113433554393. The next prime is 113433554467. The reversal of 113433554450 is 54455334311.
It can be written as a sum of positive squares in 6 ways, for example, as 98729809369 + 14703745081 = 314213^2 + 121259^2 .
It is a super-2 number, since 2×1134335544502 (a number of 23 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 885674 + ... + 1005626.
Almost surely, 2113433554450 is an apocalyptic number.
113433554450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
113433554450 is a deficient number, since it is larger than the sum of its proper divisors (97565771458).
113433554450 is a wasteful number, since it uses less digits than its factorization.
113433554450 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 138878 (or 138873 counting only the distinct ones).
The product of its (nonzero) digits is 216000, while the sum is 38.
Adding to 113433554450 its reverse (54455334311), we get a palindrome (167888888761).
The spelling of 113433554450 in words is "one hundred thirteen billion, four hundred thirty-three million, five hundred fifty-four thousand, four hundred fifty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •