Base | Representation |
---|---|
bin | 11001110100001001101101… |
… | …011111100111000100111111 |
3 | 112212222211200112102021200121 |
4 | 121310021231133213010333 |
5 | 104340124141120134120 |
6 | 1041245132103435411 |
7 | 32625430126163362 |
oct | 3164115537470477 |
9 | 485884615367617 |
10 | 113535002505535 |
11 | 331a2a19076896 |
12 | 10897a16755b67 |
13 | 4b473c683c360 |
14 | 20071a2a1a0d9 |
15 | d1d48c9625aa |
hex | 67426d7e713f |
113535002505535 has 32 divisors (see below), whose sum is σ = 152024237225280. Its totient is φ = 80865096619008.
The previous prime is 113535002505527. The next prime is 113535002505541. The reversal of 113535002505535 is 535505200535311.
It is not a de Polignac number, because 113535002505535 - 23 = 113535002505527 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113535002505491 and 113535002505500.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 279088774 + ... + 279495283.
It is an arithmetic number, because the mean of its divisors is an integer number (4750757413290).
Almost surely, 2113535002505535 is an apocalyptic number.
113535002505535 is a deficient number, since it is larger than the sum of its proper divisors (38489234719745).
113535002505535 is a wasteful number, since it uses less digits than its factorization.
113535002505535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 558584187.
The product of its (nonzero) digits is 843750, while the sum is 43.
The spelling of 113535002505535 in words is "one hundred thirteen trillion, five hundred thirty-five billion, two million, five hundred five thousand, five hundred thirty-five".
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