Base | Representation |
---|---|
bin | 1010010110001111001111… |
… | …1100101000010100111001 |
3 | 1111021122110021022122102112 |
4 | 2211203303330220110321 |
5 | 2442400414014011423 |
6 | 40110333055142105 |
7 | 2252654532466661 |
oct | 245436374502471 |
9 | 44248407278375 |
10 | 11377166157113 |
11 | 369703576a179 |
12 | 1338b79b14935 |
13 | 646b2923b353 |
14 | 2b492cd3d1a1 |
15 | 14ae2d664a78 |
hex | a58f3f28539 |
11377166157113 has 2 divisors, whose sum is σ = 11377166157114. Its totient is φ = 11377166157112.
The previous prime is 11377166157101. The next prime is 11377166157293. The reversal of 11377166157113 is 31175166177311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11234616868864 + 142549288249 = 3351808^2 + 377557^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11377166157113 is a prime.
It is not a weakly prime, because it can be changed into another prime (11377166159113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5688583078556 + 5688583078557.
It is an arithmetic number, because the mean of its divisors is an integer number (5688583078557).
Almost surely, 211377166157113 is an apocalyptic number.
It is an amenable number.
11377166157113 is a deficient number, since it is larger than the sum of its proper divisors (1).
11377166157113 is an equidigital number, since it uses as much as digits as its factorization.
11377166157113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 555660, while the sum is 50.
The spelling of 11377166157113 in words is "eleven trillion, three hundred seventy-seven billion, one hundred sixty-six million, one hundred fifty-seven thousand, one hundred thirteen".
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