Base | Representation |
---|---|
bin | 1010010111110101100100… |
… | …0011010100011111111101 |
3 | 1111101021100102112212122020 |
4 | 2211331121003110133331 |
5 | 2443323141321313001 |
6 | 40131114332110353 |
7 | 2254646263225062 |
oct | 245753103243775 |
9 | 44337312485566 |
10 | 11404632213501 |
11 | 36a774a62592a |
12 | 13423643053b9 |
13 | 6495b564b017 |
14 | 2b5db6a1cc69 |
15 | 14b9d9aaa736 |
hex | a5f590d47fd |
11404632213501 has 4 divisors (see below), whose sum is σ = 15206176284672. Its totient is φ = 7603088142332.
The previous prime is 11404632213473. The next prime is 11404632213511. The reversal of 11404632213501 is 10531223640411.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11404632213501 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11404632213511) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1900772035581 + ... + 1900772035586.
It is an arithmetic number, because the mean of its divisors is an integer number (3801544071168).
Almost surely, 211404632213501 is an apocalyptic number.
It is an amenable number.
11404632213501 is a deficient number, since it is larger than the sum of its proper divisors (3801544071171).
11404632213501 is an equidigital number, since it uses as much as digits as its factorization.
11404632213501 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3801544071170.
The product of its (nonzero) digits is 17280, while the sum is 33.
Adding to 11404632213501 its reverse (10531223640411), we get a palindrome (21935855853912).
The spelling of 11404632213501 in words is "eleven trillion, four hundred four billion, six hundred thirty-two million, two hundred thirteen thousand, five hundred one".
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