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11412343433 is a prime number
BaseRepresentation
bin10101010000011101…
…01000101010001001
31002110100100010002102
422220032220222021
5141333024442213
65124234043145
7552544214201
oct125016505211
932410303072
1011412343433
114926a74597
122265b794b5
1310cb49b34a
147a3969401
1546bd90158
hex2a83a8a89

11412343433 has 2 divisors, whose sum is σ = 11412343434. Its totient is φ = 11412343432.

The previous prime is 11412343421. The next prime is 11412343447. The reversal of 11412343433 is 33434321411.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9933710224 + 1478633209 = 99668^2 + 38453^2 .

It is a cyclic number.

It is not a de Polignac number, because 11412343433 - 28 = 11412343177 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11412343396 and 11412343405.

It is not a weakly prime, because it can be changed into another prime (11412343133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706171716 + 5706171717.

It is an arithmetic number, because the mean of its divisors is an integer number (5706171717).

Almost surely, 211412343433 is an apocalyptic number.

It is an amenable number.

11412343433 is a deficient number, since it is larger than the sum of its proper divisors (1).

11412343433 is an equidigital number, since it uses as much as digits as its factorization.

11412343433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 10368, while the sum is 29.

Adding to 11412343433 its reverse (33434321411), we get a palindrome (44846664844).

The spelling of 11412343433 in words is "eleven billion, four hundred twelve million, three hundred forty-three thousand, four hundred thirty-three".