Base | Representation |
---|---|
bin | 10101010000011101… |
… | …01000110011000011 |
3 | 1002110100100010212112 |
4 | 22220032220303003 |
5 | 141333030002003 |
6 | 5124234045535 |
7 | 552544215644 |
oct | 125016506303 |
9 | 32410303775 |
10 | 11412344003 |
11 | 4926a74a65 |
12 | 2265b798ab |
13 | 10cb49b698 |
14 | 7a39696cb |
15 | 46bd903d8 |
hex | 2a83a8cc3 |
11412344003 has 2 divisors, whose sum is σ = 11412344004. Its totient is φ = 11412344002.
The previous prime is 11412343993. The next prime is 11412344023. The reversal of 11412344003 is 30044321411.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11412344003 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11412344003.
It is not a weakly prime, because it can be changed into another prime (11412344023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706172001 + 5706172002.
It is an arithmetic number, because the mean of its divisors is an integer number (5706172002).
Almost surely, 211412344003 is an apocalyptic number.
11412344003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11412344003 is an equidigital number, since it uses as much as digits as its factorization.
11412344003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 11412344003 its reverse (30044321411), we get a palindrome (41456665414).
The spelling of 11412344003 in words is "eleven billion, four hundred twelve million, three hundred forty-four thousand, three".
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