Base | Representation |
---|---|
bin | 10000100111100110000… |
… | …010000111000100000111 |
3 | 11001011202201201210121212 |
4 | 100213212002013010013 |
5 | 122202332031140333 |
6 | 2232350033002035 |
7 | 145336313553551 |
oct | 20474602070407 |
9 | 4034681653555 |
10 | 1142025646343 |
11 | 40036a78311a |
12 | 1653ba0b331b |
13 | 8390071432a |
14 | 3d3baac84d1 |
15 | 1ea90214448 |
hex | 109e6087107 |
1142025646343 has 2 divisors, whose sum is σ = 1142025646344. Its totient is φ = 1142025646342.
The previous prime is 1142025646283. The next prime is 1142025646369. The reversal of 1142025646343 is 3436465202411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1142025646343 - 216 = 1142025580807 is a prime.
It is a super-3 number, since 3×11420256463433 (a number of 37 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1142025646343.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1142025646393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571012823171 + 571012823172.
It is an arithmetic number, because the mean of its divisors is an integer number (571012823172).
Almost surely, 21142025646343 is an apocalyptic number.
1142025646343 is a deficient number, since it is larger than the sum of its proper divisors (1).
1142025646343 is an equidigital number, since it uses as much as digits as its factorization.
1142025646343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 414720, while the sum is 41.
The spelling of 1142025646343 in words is "one trillion, one hundred forty-two billion, twenty-five million, six hundred forty-six thousand, three hundred forty-three".
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