Base | Representation |
---|---|
bin | 10000101000100011010… |
… | …001010111010010001001 |
3 | 11001021102022222120111112 |
4 | 100220203101113102021 |
5 | 122211433040230423 |
6 | 2233040013540105 |
7 | 145403630441444 |
oct | 20504321272211 |
9 | 4037368876445 |
10 | 1143053055113 |
11 | 400847717582 |
12 | 1656461a4635 |
13 | 83a35529c08 |
14 | 3d47732c65b |
15 | 1eb0050ba78 |
hex | 10a23457489 |
1143053055113 has 2 divisors, whose sum is σ = 1143053055114. Its totient is φ = 1143053055112.
The previous prime is 1143053055097. The next prime is 1143053055121. The reversal of 1143053055113 is 3115503503411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1142583552889 + 469502224 = 1068917^2 + 21668^2 .
It is a cyclic number.
It is not a de Polignac number, because 1143053055113 - 24 = 1143053055097 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1143053055113.
It is not a weakly prime, because it can be changed into another prime (1143053055163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571526527556 + 571526527557.
It is an arithmetic number, because the mean of its divisors is an integer number (571526527557).
Almost surely, 21143053055113 is an apocalyptic number.
It is an amenable number.
1143053055113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1143053055113 is an equidigital number, since it uses as much as digits as its factorization.
1143053055113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13500, while the sum is 32.
Adding to 1143053055113 its reverse (3115503503411), we get a palindrome (4258556558524).
The spelling of 1143053055113 in words is "one trillion, one hundred forty-three billion, fifty-three million, fifty-five thousand, one hundred thirteen".
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