Base | Representation |
---|---|
bin | 11001111111100000010001… |
… | …100011010010011011011011 |
3 | 112222202102100221022002220101 |
4 | 121333200101203102123123 |
5 | 104440414403331413111 |
6 | 1043043352511440231 |
7 | 33035665556452306 |
oct | 3177402143223333 |
9 | 488672327262811 |
10 | 114315144013531 |
11 | 3347386467361a |
12 | 109a305a526077 |
13 | 4ba2b44528936 |
14 | 2032c4d7b3b3d |
15 | d338ec63bbc1 |
hex | 67f8118d26db |
114315144013531 has 2 divisors, whose sum is σ = 114315144013532. Its totient is φ = 114315144013530.
The previous prime is 114315144013523. The next prime is 114315144013583. The reversal of 114315144013531 is 135310441513411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114315144013531 - 23 = 114315144013523 is a prime.
It is a super-2 number, since 2×1143151440135312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (114315144013331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57157572006765 + 57157572006766.
It is an arithmetic number, because the mean of its divisors is an integer number (57157572006766).
Almost surely, 2114315144013531 is an apocalyptic number.
114315144013531 is a deficient number, since it is larger than the sum of its proper divisors (1).
114315144013531 is an equidigital number, since it uses as much as digits as its factorization.
114315144013531 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 43200, while the sum is 37.
Adding to 114315144013531 its reverse (135310441513411), we get a palindrome (249625585526942).
The spelling of 114315144013531 in words is "one hundred fourteen trillion, three hundred fifteen billion, one hundred forty-four million, thirteen thousand, five hundred thirty-one".
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