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114315144013551 = 31319259271507821
BaseRepresentation
bin11001111111100000010001…
…100011010010011011101111
3112222202102100221022002221010
4121333200101203102123233
5104440414403331413201
61043043352511440303
733035665556452335
oct3177402143223357
9488672327262833
10114315144013551
1133473864673638
12109a305a526093
134ba2b44528950
142032c4d7b3b55
15d338ec63bbd6
hex67f8118d26ef

114315144013551 has 96 divisors (see below), whose sum is σ = 176825407933440. Its totient is φ = 65273801529600.

The previous prime is 114315144013531. The next prime is 114315144013583. The reversal of 114315144013551 is 155310441513411.

It is not a de Polignac number, because 114315144013551 - 215 = 114315143980783 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (39).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114315144013531) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 224855221 + ... + 225363041.

It is an arithmetic number, because the mean of its divisors is an integer number (1841931332640).

Almost surely, 2114315144013551 is an apocalyptic number.

114315144013551 is a deficient number, since it is larger than the sum of its proper divisors (62510263919889).

114315144013551 is a wasteful number, since it uses less digits than its factorization.

114315144013551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 508205 (or 508186 counting only the distinct ones).

The product of its (nonzero) digits is 72000, while the sum is 39.

Adding to 114315144013551 its reverse (155310441513411), we get a palindrome (269625585526962).

The spelling of 114315144013551 in words is "one hundred fourteen trillion, three hundred fifteen billion, one hundred forty-four million, thirteen thousand, five hundred fifty-one".