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114315144013583 is a prime number
BaseRepresentation
bin11001111111100000010001…
…100011010010011100001111
3112222202102100221022002222022
4121333200101203102130033
5104440414403331413313
61043043352511440355
733035665556452412
oct3177402143223417
9488672327262868
10114315144013583
1133473864673667
12109a305a5260bb
134ba2b44528976
142032c4d7b3b79
15d338ec63bc08
hex67f8118d270f

114315144013583 has 2 divisors, whose sum is σ = 114315144013584. Its totient is φ = 114315144013582.

The previous prime is 114315144013531. The next prime is 114315144013597. The reversal of 114315144013583 is 385310441513411.

It is a strong prime.

It is an emirp because it is prime and its reverse (385310441513411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114315144013583 - 212 = 114315144009487 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114315144013523) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57157572006791 + 57157572006792.

It is an arithmetic number, because the mean of its divisors is an integer number (57157572006792).

Almost surely, 2114315144013583 is an apocalyptic number.

114315144013583 is a deficient number, since it is larger than the sum of its proper divisors (1).

114315144013583 is an equidigital number, since it uses as much as digits as its factorization.

114315144013583 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 345600, while the sum is 44.

Adding to 114315144013583 its reverse (385310441513411), we get a palindrome (499625585526994).

The spelling of 114315144013583 in words is "one hundred fourteen trillion, three hundred fifteen billion, one hundred forty-four million, thirteen thousand, five hundred eighty-three".