Base | Representation |
---|---|
bin | 110101001111010110… |
… | …0011101010001010111 |
3 | 101221002222002021001220 |
4 | 1222132230131101113 |
5 | 3333122342312210 |
6 | 124305003021423 |
7 | 11155146412464 |
oct | 1523654352127 |
9 | 357088067056 |
10 | 114331604055 |
11 | 44540234379 |
12 | 1a1a950a873 |
13 | aa20a33526 |
14 | 57685b666b |
15 | 2e92520c70 |
hex | 1a9eb1d457 |
114331604055 has 64 divisors (see below), whose sum is σ = 194109696000. Its totient is φ = 57303821952.
The previous prime is 114331604047. The next prime is 114331604063. The reversal of 114331604055 is 550406133411.
It is a happy number.
It is an interprime number because it is at equal distance from previous prime (114331604047) and next prime (114331604063).
It is not a de Polignac number, because 114331604055 - 23 = 114331604047 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 22597116 + ... + 22602174.
It is an arithmetic number, because the mean of its divisors is an integer number (3032964000).
Almost surely, 2114331604055 is an apocalyptic number.
114331604055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
114331604055 is a deficient number, since it is larger than the sum of its proper divisors (79778091945).
114331604055 is a wasteful number, since it uses less digits than its factorization.
114331604055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5708.
The product of its (nonzero) digits is 21600, while the sum is 33.
Adding to 114331604055 its reverse (550406133411), we get a palindrome (664737737466).
The spelling of 114331604055 in words is "one hundred fourteen billion, three hundred thirty-one million, six hundred four thousand, fifty-five".
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