114441243141131 has 4 divisors (see below), whose sum is σ = 114529207203264. Its totient is φ = 114353279079000.

The previous prime is 114441243141101. The next prime is 114441243141139. The reversal of 114441243141131 is 131141342144411.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114441243141131 is a prime.

It is a super-2 number, since 2×114441243141131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114441243141091 and 114441243141100.

It is not an unprimeable number, because it can be changed into a prime (114441243141139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43982029115 + ... + 43982031716.

It is an arithmetic number, because the mean of its divisors is an integer number (28632301800816).

Almost surely, 2^{114441243141131} is an apocalyptic number.

114441243141131 is a deficient number, since it is larger than the sum of its proper divisors (87964062133).

114441243141131 is an equidigital number, since it uses as much as digits as its factorization.

114441243141131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 87964062132.

The product of its digits is 18432, while the sum is 35.

Adding to 114441243141131 its reverse (131141342144411), we get a palindrome (245582585285542).

The spelling of 114441243141131 in words is "one hundred fourteen trillion, four hundred forty-one billion, two hundred forty-three million, one hundred forty-one thousand, one hundred thirty-one".