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1149240437 is a prime number
BaseRepresentation
bin100010010000000…
…0000010001110101
32222002111110111122
41010200000101311
54323201143222
6310012113325
740323245132
oct10440002165
92862443448
101149240437
1153a797394
12280a65845
13154131437
14ac8b9589
156ad60a42
hex44800475

1149240437 has 2 divisors, whose sum is σ = 1149240438. Its totient is φ = 1149240436.

The previous prime is 1149240431. The next prime is 1149240439. The reversal of 1149240437 is 7340429411.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 786185521 + 363054916 = 28039^2 + 19054^2 .

It is a cyclic number.

It is not a de Polignac number, because 1149240437 - 218 = 1148978293 is a prime.

Together with 1149240439, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1149240397 and 1149240406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1149240431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 574620218 + 574620219.

It is an arithmetic number, because the mean of its divisors is an integer number (574620219).

Almost surely, 21149240437 is an apocalyptic number.

It is an amenable number.

1149240437 is a deficient number, since it is larger than the sum of its proper divisors (1).

1149240437 is an equidigital number, since it uses as much as digits as its factorization.

1149240437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24192, while the sum is 35.

The square root of 1149240437 is about 33900.4489203314. The cubic root of 1149240437 is about 1047.4588396971.

Adding to 1149240437 its reverse (7340429411), we get a palindrome (8489669848).

The spelling of 1149240437 in words is "one billion, one hundred forty-nine million, two hundred forty thousand, four hundred thirty-seven".