Search a number
-
+
115051523437 is a prime number
BaseRepresentation
bin110101100100110011…
…0101110110101101101
3101222222010201221210201
41223021212232311231
53341111142222222
6124504241233501
711212040546014
oct1531146566555
9358863657721
10115051523437
114487a649474
121a36a632891
13ab06c28426
1457d6057a7b
152ed582a427
hex1ac99aed6d

115051523437 has 2 divisors, whose sum is σ = 115051523438. Its totient is φ = 115051523436.

The previous prime is 115051523429. The next prime is 115051523449. The reversal of 115051523437 is 734325150511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 113573044036 + 1478479401 = 337006^2 + 38451^2 .

It is a cyclic number.

It is not a de Polignac number, because 115051523437 - 23 = 115051523429 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 115051523396 and 115051523405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115051523417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57525761718 + 57525761719.

It is an arithmetic number, because the mean of its divisors is an integer number (57525761719).

Almost surely, 2115051523437 is an apocalyptic number.

It is an amenable number.

115051523437 is a deficient number, since it is larger than the sum of its proper divisors (1).

115051523437 is an equidigital number, since it uses as much as digits as its factorization.

115051523437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 63000, while the sum is 37.

Adding to 115051523437 its reverse (734325150511), we get a palindrome (849376673948).

The spelling of 115051523437 in words is "one hundred fifteen billion, fifty-one million, five hundred twenty-three thousand, four hundred thirty-seven".